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x^2+49+x^2=x^2+1
We move all terms to the left:
x^2+49+x^2-(x^2+1)=0
We add all the numbers together, and all the variables
2x^2-(x^2+1)+49=0
We get rid of parentheses
2x^2-x^2-1+49=0
We add all the numbers together, and all the variables
x^2+48=0
a = 1; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·1·48
Δ = -192
Delta is less than zero, so there is no solution for the equation
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